Algebra 1 Single-variable equations

Literal equations and formulas

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Questions

Question 1

49310

Make \(a\) the subject of \(b=\dfrac{a+1}{a-1}\)

Answer

\(a =\dfrac{b+1}{b-1}\)

Worked Solution

\(\begin{aligned}
b &=\frac{a+1}{a-1} \\
\frac{a+1}{a-1} &=b \\
a+1 &=b(a-1) \\
a+1 &=ba-b \\
a &=b a-b-1 \\
a-ba &=-b-1 \\
ba-a &=b+1 \\
a(b-1) &=b+1 \\
a &=\frac{b+1}{b-1}
\end{aligned}\)

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