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USA - Geometry Right triangles and trigonometry

Law of Sines

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Question 1
181861
The Law of Sines states that, in any triangle \(ABC\):
A.
\(\dfrac{a}{\sin A} = \dfrac{b}{\sin B} = \dfrac{c}{\sin C}\)
B.
\(a^2 = b^2 + c^2 - 2bc\cos A\)
C.
\(\dfrac{a}{b} = \dfrac{c}{d}\)
D.
\(\sin A = \dfrac{a}{c}\)
\(\dfrac{a}{\sin A} = \dfrac{b}{\sin B} = \dfrac{c}{\sin C}\)

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