USA - Geometry
Right triangles and trigonometry
Trigonometric ratios (sin, cos, tan) for acute angles
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Questions
Question 1
181781
In a right triangle, the sine of an acute angle \(\theta\) is equal to:
\(\dfrac{\text{opposite}}{\text{hypotenuse}}\)
\(\dfrac{\text{adjacent}}{\text{hypotenuse}}\)
\(\dfrac{\text{opposite}}{\text{adjacent}}\)
\(\dfrac{\text{hypotenuse}}{\text{opposite}}\)
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